int high = Convert.ToInt32(Console.ReadLine());
double zong = 0;//zong为一共经过的距离
int cishu = 1; //cishu为第几次落地
double tiao = high;//tiao为反弹高度
do { zong+=tiao*2; cishu++; tiao/=2;
    if (cishu == 4)
    {
        Console.WriteLine("反弹高度为" + tiao);
    }
} while (cishu <= 3);
Console.WriteLine(zong-high);

方法二：

int n = Convert.ToInt32(Console.ReadLine());
double high = n; 
int i = 1;
double sum = high;
do
{ high = high / 2;
    i++;
    sum += (2 * high);}
while (i < 11);
Console.WriteLine("落地高度" + high);
Console.WriteLine("和" + sum);

using System;

namespace _022_编程题
{
    class Program
    {
        static void Main(string[] args)
        {
            int n = Convert.ToInt32(Console.ReadLine());
            double high = n;
            for (int i = 0; i < 10; i++)
            {
                high /= 2;
            }
            Console.WriteLine("第10次落地后，会反弹的高度是：" + high);
            //  1 --- 2n
            //  2 --- n
            //  3 --- n/2
            // 10 --- d(9)/2
            double distance = 2 * n;
            double sum = n;
            for (int i = 0; i < 9; i++)
            {
                distance /= 2;
                sum += distance;
            }
            Console.WriteLine("第10次落地后经过了多少米：" + sum);
        }
    }
}

            double qiu = Convert.ToDouble(Console.ReadLine());
            double sum = 0.0;
            double a = qiu;
            for (int i = 0; i <10; i++)
            {
                sum = qiu * 2.0 + sum;
                qiu =qiu/ 2.0;
                

            }
            Console.WriteLine(qiu);
            Console.WriteLine((sum-a));

            double n = Convert.ToInt32(Console.ReadLine());
            double sum = 0;
            for (int i=0; i<10; i++) 
            {
                sum += n+n/2;
                n /= 2;
            }
            Console.WriteLine("第十次反弹高度为" + n + "米");
            Console.WriteLine("移动距离为" + (sum-n) + "米");

fsafasf

float hight = new Random().Next(1, 100); //获取随机测试数据 Console.WriteLine("初始高度：{0}", hight); float sum = 0f; for (int i = 0; i < 10; i++) { sum += (float)(hight + hight / 2.0); hight /= 2; Console.WriteLine("第{0}次反弹，弹起高度 -> {1}", i, hight); } Console.WriteLine("经过的总距离 -> {0}", sum);

第六十一课  编程题

1. 一个球从某一高度落下来，每次落地后反跳回原来高度的一半，再落下。编程计算球第10次反弹多高？在第10次落地时，共经过多少米？输入球的初始高度，输出反弹多高，和经过了多少米？

double n=  Convert.ToInt32(Console.ReadLine());
double hi = n;

for (int i = 0; i < 10; i++)
{
    hi /= 2;
}
Console.WriteLine(hi);

double zhi = 2 * n;
double sun = n;
for (int i = 0; i < 9; i++)
{
    zhi /= 2;
    sun += zhi;
}   
Console.WriteLine(sun);

多画一画，多数一数就没问题了，我相信我不会有问题，差点没被这题给绕死，脑子是个号东西，我得长一个了。